5x^2-4x=3x-21x^2

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Solution for 5x^2-4x=3x-21x^2 equation:



5x^2-4x=3x-21x^2
We move all terms to the left:
5x^2-4x-(3x-21x^2)=0
We get rid of parentheses
5x^2+21x^2-3x-4x=0
We add all the numbers together, and all the variables
26x^2-7x=0
a = 26; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·26·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*26}=\frac{0}{52} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*26}=\frac{14}{52} =7/26 $

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